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Example 1
Find the partial derivatives of the function f(x, y) = x2 + 3xy - 8y at the point (2, -1). To find fx(x, y), we treat y as a constant, fx(x,y) = 2x+3y. To find fy(x, y), we treat x as a constant, fy(x,y) = 3x - 8. Thus fx(2, -1) = 2 · 2 + 3(-l) = 1, fy(2, -1) = 3 · 2 - 8 = -2. Figure 11.3.2 shows the surface z = f(x, y) and the tangent lines at the point (2,-1). Figure 11.3.2
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