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Home Interstage Coupling Constructing The New Load Line | |||||
See also: The Split-Load Circuit, The Effect of Changing the Load, Load-Line Construction, Finding the Plate Resistance | |||||
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Constructing The New Load LineAuthor: N.H. Crowhurst We can apply these facts to the load line. The actual load resistor connected between B+ and the plate controls the steady operating point, according to the steady grid bias voltage. This operating point is found by using the load line corresponding to the coupling resistor, starting from the B+ voltage used. Audio fluctuations cause the plate current and voltage to fluctuate in a manner that can be indicated by drawing a load line through the operating point, at a slope representing the combined resistances of the coupling resistor and grid resistor in parallel. In the example we used before, the plate coupling resistor was 20000 ohms. If we use a grid resistor of 100000 ohms, the effective resistance of these two working in parallel for (audio only) is (20000 x 100000)/(20000 + 100000) or 16670 ohms. Drawing a line representing this resistance, through the 175-volt/3.75-milliampere operating point, can be achieved as follows: three milliamps through 16670 ohms will produce a voltage drop across it of 50 volts. Hence 6,75 milliamps on this load line will correspond with 175-50 or 125 volts.
Joining these points and extending the line we can find the new values of plate voltage corresponding to fluctuation of grid voltage between -5 and -10. The new voltages, instead of 150 and 200, as on the 20000-ohm load line, are now 152 and 198 volts. Thus a 5-volt input fluctuation yields a 46-volt output fluctuation. The gain is 46/5 or 9.2, instead of the 10 obtained before.
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Home Interstage Coupling Constructing The New Load Line |