Example 6
Find the maximum and minimum, if any, of the function
![11_partial_differentiation-476.gif](img/11_partial_differentiation-476.gif)
Step 1 |
The domain is the whole (x, y) plane because the denominator is always positive. |
Step 2 |
= -[2(x + y) + 2(x + l)][(x + y)2 + (x + 1)2 + y2] -2, = -[2(x + y) + 2y][(x + y)2 + (x + 1)2 + y2] -2.
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Step 3 |
The partial derivatives are zero when
2(x + y) + 2(x + 1) = 0, 2(x + y) + 2y = 0,
or
2x + y + 1 = 0, x + 2y = 0.
The critical point is
x = -⅔, y = ⅓, and z = 3. |
Step 4 |
Let E be the hyperreal region -H ≤ x ≤ H, -H ≤ y ≤ H where H is positive infinite. |
Step 5 |
At a boundary point of E where x = ±H, (x + 1)2 is infinite so z is infinitesimal. At a boundary point where y = ±H, y2 is infinite so again z is infinitesimal. |
CONCLUSION
z has a maximum of 3 at the critical point (-⅔, ⅓). z has no minimum. The region E is sketched in Figure 11.7.12.
![11_partial_differentiation-479.gif](img/11_partial_differentiation-479.gif)
Figure 11.7.12
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