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Home Applications of the Integral Some Applications to Physics Examples Example 2 | |
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Example 2
A circular disc of radius r has density at each point equal to the distance of the point from the y-axis. Find its mass. (The center of the circle, shown in Figure 6.6.4, is at the origin.) The circle is the region between the curves - and from -r to r. The density at a point (x, y) in the disc is |x|. By symmetry, all four quadrants have the same mass. We shall find the mass m1 of the first quadrant and multiply by four. Put u = r2 - x2, du = -2xdx; u = r2 when x = 0, and u = 0 when x = r. Then m = 4m1 = (4/3)r3. Figure 6.6.4
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Home Applications of the Integral Some Applications to Physics Examples Example 2 |